WTA SE w960i LCD crack.

werm — Sun, 12 Apr 2009 13:04:43 +0800

Hi. I want to ask about the cheaper price of the lcd replacement for my W960i. My lcd crack and i want to replace with a new one. Hopefully there's a shop near putrajaya, serdang or sri kembangan. Asked the price with the phone shop near my home. They said around RM350. Hope anybody will reply to my post please. Thanks in advance.

need help for my assignment plz...

werm — Mon, 10 Sep 2007 22:22:42 +0800

Greetings..
I seeking your help for Sifting or Special Phone Number. It will be like this..

It's about special phone numbers. The numbers are special because they can easily be translated into numbers. If I key in the word vincent , the phone number will come out as what we may see at the phone and the alphabets above the number which the result will be 8462368...

as I doing the codes which I pasted it below..the non-fatal error occured...so may I know what is really the mistakes have I done and hopefully you may teach me how to solve it..

For your information, I'm using Knoppix..

CODE

CODE

#include <stdio.h>
#include <string.h>
#define SIZE 20

char* numberChecker( char word[] );
char digitConverter( char alphabets );

int main( void )

{

char *words;
char *noPtr;

int count = 0;
int totalCount = 0;

FILE *dfPtr;
FILE *ofPtr;

dfPtr = fopen( "dictionary.txt", "r" );
ofPtr = fopen( "output.txt", "w" );

if( dfPtr == NULL ) {
printf( "Error! File could not be opened for input.\n" );
}

else if ( ofPtr == NULL ) {
printf( "Error! File could not be opened for output.\n" );
}

else {
while( fgets( words, SIZE, dfPtr ) != NULL ) {

noPtr = numberChecker( words );

if( noPtr[ 7 ] == '\0' ) {
fprintf( ofPtr, "The word %s is the phone number %c%c%c-%c%c%c%c\n",
words, noPtr[ 0 ], noPtr[ 1 ], noPtr[ 2 ], noPtr[ 3 ],
noPtr[ 4 ], noPtr[ 5 ], noPtr[ 6 ] );
count++;
}

else if( noPtr[ 10 ] == '\0' ) {
fprintf( ofPtr, "The word %s is the phone number %c%c%c-%c%c%c-%c%c%c%c\n",
words, noPtr[ 0 ], noPtr[ 1 ], noPtr[ 2 ], noPtr[ 3 ],
noPtr[ 4 ], noPtr[ 5 ], noPtr[ 6 ], noPtr[ 7 ], noPtr[ 8 ],
noPtr[ 9 ] );
count++;
}

else;

totalCount++;
}
}

fprintf( ofPtr, "\n%.1f percent of the 7/10 letter words were translatable into phone numbers\n",
(count / (float)totalCount) * 100.0);

printf("%.1f percent of the 7/10 letter words were translatable into phone numbers\n",
(count / (float)totalCount) * 100.0);

fclose( dfPtr );
fclose( ofPtr );

return 0;
}

char* numberChecker( char word[] )
{
int length;
int i;
static char phNumber[ SIZE ];
char letter;

length = strlen( word ) - 1;

if( length == 7 || length == 10 ) {
for(i = 0; i < length; i++ ) {
letter = word[ i ];
phNumber[ i ] = digitConverter( letter );
}
phNumber[ length ] = '\0';
}

else
phNumber[ 0 ] = '\0';

return phNumber;
}

char digitConverter( char alphabets )
{
char digit;

switch( alphabets )

{

case 'A':
case 'a':
case 'B':
case 'b':
case 'C':
case 'c':
digit = '2';
break;

case 'D':
case 'd':
case 'E':
case 'e':
case 'F':
case 'f':
digit = '3';
break;

case 'G':
case 'g':
case 'H':
case 'h':
case 'I':
case 'i':
digit = '4';
break;

case 'J':
case 'j':
case 'K':
case 'k':
case 'L':
case 'l':
digit = '5';
break;

case 'M':
case 'm':
case 'N':
case 'n':
case 'O':
case 'o':
digit = '6';
break;

case 'P':
case 'p':
case 'R':
case 'r':
case 'S':
case 's':
digit = '7';
break;

case 'T':
case 't':
case 'U':
case 'u':
case 'V':
case 'v':
digit = '8';
break;

case 'W':
case 'w':
case 'X':
case 'x':
case 'Y':
case 'y':
digit = '9';
break;

default:
digit = '0';
break;
}

return digit;
}

with best regards!
werm

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WTA SE w960i LCD crack.

need help for my assignment plz...